2.483*(10^-5)=x^2/0.2-x

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Solution for 2.483*(10^-5)=x^2/0.2-x equation: 


x in (-oo:+oo)

2.483*10^-5 = (x^2)/0.2-x // - (x^2)/0.2-x

x-((x^2)/0.2)+2.483*10^-5 = 0

x-5*x^2+2.483*10^-5 = 0

x-5*x^2+0.00002483 = 0

DELTA = 1^2-(-5*0.00002483*4)

DELTA = 1.0004966

DELTA > 0

x = (1.0004966^(1/2)-1)/(-5*2) or x = (-1.0004966^(1/2)-1)/(-5*2)

x = (1.0004966^(1/2)-1)/(-10) or x = (1.0004966^(1/2)+1)/10

x in { (1.0004966^(1/2)-1)/(-10), (1.0004966^(1/2)+1)/10 }

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